1. m(A)= 52g m(rozt.) = m(A)+m(rozp.) = 52 + 48 = 100g
m(rozp.)=48g V = m/hustota = 100/1,25 = 80 cm3
hustota = 1,25g/cm3 w(A) = m(A)/m(rozt.) = 52/100 = 0,52
M=342,297g/mol c=n/V = m(A)/M.V
w(A) = ? c = 52/342,297.0,08
c = ? mol/dm3 c = 1,89 mol/dm3

2. V=100cm3=0,1dm3 m(rozt.)= V.hustota = 100.1,2192 = 121,92 g
w=20% = 0,2 m(A)=w.m(rozt.) = 0,2.121,92 = 24,384g
hustota = 1,2192g/cm3 c=m(A)/M.V
M(NaOH)= 39,997g/mol c= 24,384/39,997.0,1
m(A)=?g c = 6,09 mol/dm3
c=? mol/dm3

3. c=3,47mol/dm3 w(A)=c.M/hustota
hustota = 1,13g/cm3 = 1130g/dm3 w(A)= 3,47.39,997/1130
M(NaOH)= 39,997g/mol w(A) = 0,1228 = 12,28%
w(A)= ?