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Chcela by som sa opýtať prečo je uprava tejto rovnice: X^(log^2x-3logx+1)=1000 Takato: (log^2x-3logx+1)(log x)=log 1000
Dobrý deň chcela by som sa spýtať či mám správny postup a ak hej tak ako pokračovať ďalej. Ďakujem
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