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Kinematika

Určte kinematické veličiny ako fukciu času

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Tomáš Č.
Tomáš Č. Contact
Cieľom úlohy je derivovať, rýchlosť je def. pre zložky x, ako smer vodorovný v(x) = d(x)/dt, vertikálna zložka v(y) = d(y)/dt, zrýchlenie a(x) = d(v(x))/dt, a(y) = d(v(y))/dt, a veľkosti vektorov je pytagorova veta lebo veľkosť vektora je prepona a tie dve zložky sú odvesna, čiže v = sqrt(v(x)^2+v(y)^2) a pre veľkosť zrýchlenia to isté s a = sqrt(a(x)^2+a(y)^2), sqrt je odmocnina druhá dúfam, že viete Pytagorovu vetu.
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