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Prosím o pomoc s výpočtom príkladu:
Bodové elektrické náboje q1 a q2 sú vo vzduchu vo vzájomnej vzdialenosti a1 = 4cm. Elektrická sila pôsobiaca medzi nábojmi je kompenzovaná vonkajšou silou, takže náboje sú v rovnováhe. Ak ponoríme oba náboje do kvapaliny, vzdialenosť medzi nábojmi sa zmení na a2 = 7cm. Vypočítajte relatívnu permitivitu kvapaliny ak predpokladáme, že sila udržujúca náboje v rovnováhe sa pri ponorení do kvapaliny nezmení.
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