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Viera K.
chémia

Riedenie koncentrovanej kyseliny

Mám k dispozícii koncentrovanú 68% HNO3, chcem pripraviť 250 ml 25%-nej HNO3. Ako to vypočítam? Ďakujem

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Tomáš Č.
Tomáš Č. Contact
Dobrý deň
V1(pridaní)=Rho(25%)*w(25%)*V(celkový)/(Rho(68%)*w(68)) hustoty zistíte z tabuliek kyselina dusičná ich má a zlomky 0,25 a 0,68 a objem 0,25 litrov.
V1(pridaní)=1,1469*0,25*250/(1,40456*0,68))= 75,051= 75,1 ml hustotu 68% som získal interpoláciou
Comments:
Viera K.
Ďakujem Vám
Tomáš Č.
a začalo sa to takto n1=n2, c1*V1=c2*V2 bilancia voda je nula vždy je to rozpúšťadlo a není tam ta latka o nejaké koncentracií preto aj nula c=n(látka)/V(roztok)=m(látka)/(M(látka)*V(roztok))=m(roztok)*w(látka)/(V(roztok)*M(látka))=Rho(látka)w(látka)*V(roztok)/(M(látka*V(roztok))=Rho(látka)*w(látka)/M(látka)
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