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V 1. kole súťažilo proti sebe 8 dvojíc. Koľkými spôsobmi môžeme z nich vytvoriť 8 nových súťažných dvojíc pre 2. kolo (čiže žiadna dvojica z 1. kola sa nestretne opäť v 2. kole)?
Pokyny. Výsledok vyjadrite pomocou súčtovej notácie
V 7cm3 sa rozpustilo 10g kyseliny šťaveľovej,H2C2O4.2H2O. Za stáleho miešania sa pridával roztok 6,7g NaOH v 17cm3 vody. Aká je výťažnosť reakcie ak sme navážili 9,73g vzniknutého šťavelanu sodného? …
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